The next headings contain details on crucial aspects for assortment and proper utilization of gearbox.
For specific data on the gearbox selection,see the pertinent chapters.
one.0 OUTPUT TORQUE
one.one Rated output torque
Mn2 [Nm]
The torque that will be transmitted continuously by way of the output shaft, together with the gear unit operated below a services issue fs = one.
one.2 Demanded torque
Mr2 [Nm]
The torque demand primarily based on application requirement. It is encouraged to become equal to or significantly less than torque Mn2 the gearbox beneath examine is rated for.
one.three Calculated torque
Mc2 [Nm]
Computational torque worth for being employed when choosing the gearbox.
It is actually calculated considering the needed torque Mr2 and support aspect fs, as per the romance here soon after:Mc2 = Mr2 ?¡è fs ?¨¹ Mn2
two.0 Energy
two.1 Rated input electrical power
Pn1 [kW]
The parameter is often discovered during the gearbox rating charts and represents the KW that can be safely transmitted to the gearbox, primarily based on input velocity n1 and support factor fs= 1.
2.two Rated output energy
Pn2 [kW]
This worth will be the electrical power transmitted at gearbox output. it can be calculated using the following formulas:
Pn2 = Pn1 ?¡è |?d
Pn2= Mn2*n2/9550
three.0 EFFICIENCY
Efficiency is actually a parameter which includes a important influence over the sizing of sure applications, and mainly will depend on gear pair designelements. The mesh information table on webpage 9 exhibits dynamic efficiency (n1=1400)and static efficiency values.
Recall that these values are only accomplished following the unit has become run in and it is with the working temperature.
three.1 Dynamic efficiency
[|?d]
The dynamic efficiency is the relationship of electrical power delivered at output shaft P2 to power utilized at input shaft P1:
|?d =P2/P1
three.2 Static efficiency[|?s]
Efficiency obtained at start-up from the gearbox. Whilst this is often commonly not considerable component for helical gears, it might be alternatively significant when picking worm gearmotors working beneath intermittent duty.
four.0 Service Component
The support component (fs ) depends on the operating problems the gearbox is subjected to your parameters that have to be taken into consideration to pick essentially the most satisfactory servies issue correctly comprise:
1. type of load in the operated machine : A – B – C
two. length of day by day working time: hours/day(?¡Â)
3. start-up frequency: starts/hour (*)
Form of LOAD: JDLB3A – uniform,fa?¨¹0.three
B – moderate shocks, fa?¨¹3
C – hefty shocks, fa?¨¹10
fa=Je/Jm
–Je(kgm2) second in the external inertia reduced at the drive shaft
–Jm(kgm2) moment of inertia of motor
–If fa>10 please contact our Technical Service
A -Screw feeders for light products, supporters, assembly lines, conveyor belts for light products, modest mixers, lifts, cleansing machines, fillers, management machines.
B -Winding devices, woodworking machine feeders, goods lifts, balancers,threading machines, medium mixers, conveyor belts for heavy materials,winches, sliding doors, fertilizer scrapers, packing machines, concrete mixers, crane mechanisms, milling cutters, folding machines, gear pumps.
C -Mixers for hefty products, shears, presses, centrifuges, rotating supports, winches and lifts for hefty components, grinding lathes, stone mills, bucket elevators, drilling machines, hammer mills, cam presses, folding machines, turntables, tumbling barrels, vibrators, shredders.